36x^2+36x-187=0

Solution for 36x^2+36x-187=0 equation:

36x^2+36x-187=0

a = 36; b = 36; c = -187;
Δ = b2-4ac
Δ = 362-4·36·(-187)
Δ = 28224
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{28224}=168$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-168}{2*36}=\frac{-204}{72}
=-2+5/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+168}{2*36}=\frac{132}{72}
=1+5/6
$